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lifesting
Post subject: How do I draw an implement class for a interface using UML?  PostPosted: Jan 12, 2006 - 05:12 PM



Joined: Aug 20, 2004
Posts: 2

I created an interface named FlyBehavior which has a sole behavior fly,
Now it need two implementation classes,one's name is FlyWithWings,the other
is FlyNoWay.I done them like this below:

Step-1 select class FlyWithWings,make it's stereoType be implementationClass.

Step-2 click 'Supplier Dependencies',inputted 'FlyBehavior' as the stereoType's name,
make the stereoType's base-class be Interface Option,and select the interface
FlyBehavior's namespace as stereotype's namespace
Step-3 save it.

Step-4 select all,click UML->Jenerate Java.

ok,the java code for interface and implemantation class was generated.
but but there's no method in class FlyWithWing and FlyNoWay,why?
I think it must have a method 'fly' as leat.

The more boring thing is that class FlyWithWing did not implement interface
FlyBehavior at all.

Is it a bug in UML designation?


Thanks for your reply!
 
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support-rkalla
Post subject:   PostPosted: Jan 12, 2006 - 09:33 PM
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Joined: Jan 06, 2004
Posts: 23824

We don't support this currently but it has been filed as an ehancement request and we added your comments to it.

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Riyad
MyEclipse Support
 
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